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Equivalent two-phase to ground fault admittances at Transmission nodes

asked 2017-10-08 11:26:28 -0500

EEE1993 gravatar image

Does anyone know what is "Equivalent two-phase to ground fault admittances at Transmission nodes"? How can I find it? Or how can I add it? Thank you!!

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answered 2017-10-08 14:24:53 -0500

perolofl gravatar image

It can be calculated with SCMU if your case includes sequence data.

See calculation with savnw.sav below. The equivalent impedance is shown at the bottom of the report.

     PTI INTERACTIVE POWER SYSTEM SIMULATOR--PSS(R)E     SUN, OCT 08 2017  21:19
 PSS(R)E PROGRAM APPLICATION GUIDE EXAMPLE
 BASE CASE INCLUDING SEQUENCE DATA

 UNBALANCES APPLIED:

 LINE TO LINE TO GROUND FAULT AT BUS 151 [NUCPANT     500.00]   EXCLUDED PHASE 1
   L-L Z = (0.0,0.0)   L-G Z = (0.0,0.0)


                     SEQUENCE THEVENIN IMPEDANCES AT FAULTED BUSES

   BUS# X-- NAME --X BASKV          ZERO              POSITIVE            NEGATIVE
    151 NUCPANT     500.00    0.00017  0.00600    0.00409  0.01765    0.00409  0.01765


 LINE TO LINE TO GROUND FAULT AT BUS    151 [NUCPANT     500.00]:

 SEQUENCE              RE(V0)    IM(V0)    RE(V+)    IM(V+)    RE(V-)    IM(V-)   RE(3V0)   IM(3V0)
 PHASE                 RE(VA)    IM(VA)    RE(VB)    IM(VB)    RE(VC)    IM(VC)

    151 (P.U.)         0.1930    0.0618    0.1930    0.0618    0.1930    0.0618    0.5790    0.1853
 NUCPANT     500.00    0.5790    0.1853    0.0000    0.0000    0.0000   -0.0000

 SEQUENCE              RE(I0)    IM(I0)    RE(I+)    IM(I+)    RE(I-)    IM(I-)   RE(3I0)   IM(3I0)
 PHASE                 RE(IA)    IM(IA)    RE(IB)    IM(IB)    RE(IC)    IM(IC)

 FROM    101 CKT 1    -4.8519   14.0850    9.0619   -8.6127   -0.8115    2.3904  -14.5557   42.2551
 NUC-A       21.600    3.3986    7.8627  -18.5060    8.6456    0.5518   25.7468

 FROM    102 CKT 1    -4.8519   14.0850    9.0619   -8.6127   -0.8115    2.3904  -14.5557   42.2551
 NUC-B       21.600    3.3986    7.8627  -18.5060    8.6456    0.5518   25.7468

 FROM    152 CKT 1    -0.2046    0.4339   -1.1123   -5.6030   -0.8804    0.6515   -0.6139    1.3016
 MID500      500.00   -2.1973   -4.5177   -4.6248    3.1104    6.2082    2.7088

 FROM    152 CKT 2    -0.2046    0.4339   -1.1123   -5.6030   -0.8804    0.6515   -0.6139    1.3016
 MID500      500.00   -2.1973   -4.5177   -4.6248    3.1104    6.2082    2.7088

 FROM    201 CKT 1    -1.0921    2.8011    1.4018  -14.1772   -1.9712    2.3697   -3.2762    8.4034
 HYDRO       500.00   -1.6615   -9.0063  -15.1374    5.7838   13.5227   11.6259


 SUM OF CONTRIBUTIONS INTO BUS    151 [NUCPANT     500.00]:

    151              -11.2051   31.8389   17.3011  -42.6085   -5.3549    8.4534  -33.6154   95.5168
 NUCPANT     500.00    0.7411   -2.3161  -61.3992   29.2958   27.0426   68.5371

 CONTRIBUTIONS EQUIVALENT POSITIVE SEQUENCE ADMITTANCE   17.2353 -226.2707 PU
                                                         1723.53 -22627.07 MVA


 SHUNT + LOAD CURRENT AT BUS    151 [NUCPANT     500.00]:

    151                0.0000    0.0000    0.3706   -1.1581    0.3706   -1.1581    0.0000    0.0000
 NUCPANT     500.00    0.7411   -2.3161   -0.3706    1.1581   -0.3706    1.1581


 FAULT CURRENT AT BUS    151 [NUCPANT     500.00]:

    151 ...
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Asked: 2017-10-08 11:26:28 -0500

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Last updated: Oct 08