Get names of buses in correct order.

To get the names of buses, I create a subsystem consisting of the buses I want, using psspy.bsys, then I use abuschar to get the bus names, like this:

psspy.bsys(1,0,[ 0.69, 400.],0,[],1,[buses],0,[],0,[])
ierr, carray = psspy.abuschar(1,2,'NAME')

This gives me the names in the order they are listed in PSS/E. What I want is to get the names of the buses, sorted in the same order as my list buses.

My solution has been to make multiple subsystems, and call abuschar several times. Is there a way to avoid this?

nodes = [1,2,3,10,4]

for x in range(0,len(nodes)):
   psspy.bsys(x,0,[ 0.69, 400.],0,[],1,[nodes[x]],0,[],0,[])

   ierr, carray = psspy.abuschar(x,2,'NAME')   
   names[x] = carray[0][0].strip()

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answered Jun 9 '16

SqFKYo
126 ●4

If you ask PSS/E both the numbers and the names of the buses, you'll get them back in the same order. Then to sort them you can use Python's sort combined with key-parameter such as in this example: http://stackoverflow.com/questions/13...

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Nice solution! Didn't think of that. Requires some work around, but it's clever =)

Transmission Impossible (Jun 9 '16)

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answered Sep 26 '16

SqFKYo
126 ●4

Unfortunately psspy.notona gives the EXNAME instead of NAME of the bus.

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No problem! For those who prefer the short name instead of the extended name it is just to replace the last line in my script with: names.append(name[:12].strip())

perolofl (Sep 26 '16)

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answered Sep 23 '16

perolofl

3452 ●1 ●9 ●20

This solution is simple without any unnecessary complications or work arounds...

nodes = [1,2,3,10,4]

names = []
for ibus in nodes:
  ierr,name  = psspy.notona(ibus)
  names.append(name)

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Get names of buses in correct order.

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