Revision history [back]

Hi, I use the example “sample.sav” to calculate power flow and get data of DC line ‘1’, and according to the calculation equalities to calculate the DC voltage, but there are minor differences between my results and the PSS/E results. The process of my calculation for rectifier side is: 2( 1.35EBASETR/TAPcos(a)-3/piDCAMPSXC )=532.9, while the print results is 535.9; And for the inverter side my results is 506.8 but 514.0 for PSS/E. And there is a doubt why the EBASE is different from the BUS BASKV？

Hi, I use the example “sample.sav” to calculate power flow and get data of DC line ‘1’, and according to the calculation equalities to calculate the DC voltage, but there are minor differences between my results and the PSS/E results. The process of my calculation for rectifier side is: 2( 1.35EBASETR/TAPcos(a)-3/piDCAMPSXC )=532.9, while the print results is 535.9; And for the inverter side my results is 506.8 but 514.0 for PSS/E. And there is a doubt why the EBASE is different from the BUS BASKV？

Hi, I use the example “sample.sav” to calculate power flow and get data of DC line ‘1’, and according to the calculation equalities to calculate the DC voltage, but there are minor differences between my results and the PSS/E results. The process of my calculation for rectifier side is: 2( 1.35EBASETR/TAPcos(a)-3/piDCAMPS2x( 1.35xEBASExTR/TAPxcos(a)-3/pi*DCAMPS x XC )=532.9, while the print results is 535.9; And for the inverter side my results is 506.8 but 514.0 for PSS/E. And there is a doubt why the EBASE is different from the BUS BASKV？

Hi, I use the example “sample.sav” to calculate power flow and get data of DC line ‘1’, and according to the calculation equalities to calculate the DC voltage, but there are minor differences between my results and the PSS/E results. The process of my calculation for rectifier side is: 2x( 1.35xEBASExTR/TAPxcos(a)-3/pi*DCAMPS x 2( 1.35EBASETR/TAPcos(a)-3/piDCAMPSXC )=532.9, while the print results is 535.9; And for the inverter side my results is 506.8 but 514.0 for PSS/E. And there is a doubt why the EBASE is different from the BUS BASKV？

Hi, I use the example “sample.sav” to calculate power flow and get data of DC line ‘1’, and according to the calculation equalities to calculate the DC voltage, but there are minor differences between my results and the PSS/E results. The process of my calculation for rectifier side is: 22* ( 1.35EBASETR/TAPcos(a)-3/piDCAMPS1.35* EBASE* TR/TAP* cos(a)-3/pi* DCAMPS* XC )=532.9, while the print results is 535.9; And for the inverter side my results is 506.8 but 514.0 for PSS/E. And there is a doubt why the EBASE is different from the BUS BASKV？