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The model is faithfully simulating the data you have given it.
You can do a sanity check using ohms law; if the impedance between the fault and the supply is about 10% of the impedance of the fault, then you have a voltage divider situation, and it will result in a 10% voltage drop.
When I say "between the fault and the supply" I also mean the impedance of the volage source itself; so check the MVA base of the machine that is the supply, and check its impedance.
One useful way to look at the impedance of your load flow case is to get an SLD diagram, and click on the "DAT" button, to "Display impedance data on the Active diagram"
Thank you. How can I calculate impedance between the fault and the supply ?
Asked: Apr 28 '3
Seen: 388 times
Last updated: May 03 '23
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What is the effect? Voltage drop during the fault?
It is 0.9 Un in the 220 kV buses that are far from the fault. The generation is 1300 MW and load 1150 MW.
It is just 10 % decrease in voltage. Is that abnormal?
Comparing with values of pmu (phasor measurement unit) and in my experience I think yes. Because it is a far away foult in 110 kV. In pmu the values are 0.02 Un.
Check the voltage drop at the buses between 220 and 110 kV line. Was the real fault a three phase fault?